Silver Aluminum
February 22nd, 2007
How grams of aluminum must react to displace all the silver from 79.1 g of silver nitrate?
I’m having a little trouble with this homework question. Can you please explain step by step how to do it and solve becuase my answer does not match up.
Al + 3AgNO3 –> Al(NO3)3 + 3Ag
79.1gAgNO3 / 169.87g/mole = 0.46moles AgNO3
from the balanced equation we know that 1mole of Al reacts with 3 moles of AgNO3
gAl = 0.46moles AgNO3 x (1Al/3AgNO3) x 27g/mole = 4.14gAl required
Cleaning silver with baking soda and aluminum foil (and hot water!)